Vardaan Watermark
Vardaan Learning Institute
Class 11 Physics • Chapter Notes
🌐 vardaanlearning.com📞 9508841336

Module 7: Waves and their Properties

Dear Class 12 Student! Why are waves so important? In Class 12, Chapter 10 is entirely dedicated to Wave Optics (understanding light as a wave), and Chapter 7 focuses on Alternating Current (AC), which behaves exactly like a mechanical wave in its mathematics. If you master the equations of waves, phase differences, and superposition right now, you will fly through those chapters!

1. Basic Concepts of Waves

Transverse and Longitudinal Waves

A wave is a disturbance that propagates through space and time, transferring energy and momentum from one point to another without the physical transfer of matter.

A. Transverse and Longitudinal Waves

B. Electromagnetic (Non-Mechanical) Waves

Mechanical waves (like sound) need a material medium to travel. Electromagnetic (EM) Waves do not. They consist of oscillating electric and magnetic fields and can travel through a perfect vacuum. Light, X-rays, and radio waves are all EM waves. They are strictly transverse in nature.

(Class 12 Preview: You will dedicate all of Chapter 8 to EM Waves!)

2. Wave Parameters and Terminology

Sine Wave Graph Structure

To analyze a wave mathematically, we must define its geometric and temporal characteristics.

Definitions

The Universal Wave Equation

The velocity ($v$) of a wave is the distance it travels in a given time. Since it travels a distance of one wavelength ($\lambda$) in one time period ($T$):

$$v = \frac{\lambda}{T}$$

Because $f = \frac{1}{T}$, we get the most fundamental equation of wave motion:

Formula $$v = f \lambda$$ Note: The frequency ($f$) of a wave depends ONLY on the source. It does not change when the wave moves from one medium to another. Wavelength and velocity do change!
Practice Problem 1 Question: An FM radio station broadcasts at a frequency of $100 \text{ MHz}$ ($100 \times 10^6 \text{ Hz}$). Assuming radio waves are EM waves that travel at the speed of light ($c = 3 \times 10^8 \text{ m/s}$), what is the wavelength of these radio waves?
Transverse and Longitudinal Waves
Solution:
Given: $f = 10^8 \text{ Hz}$, $v = 3 \times 10^8 \text{ m/s}$.
Using $v = f \lambda$
$\lambda = \frac{v}{f} = \frac{3 \times 10^8}{10^8} = \mathbf{3 \text{ meters}}$

3. Phase, Phase Difference, and Path Difference

This is the most critical concept for Class 12 Wave Optics (Young's Double Slit Experiment). Pay close attention!

Crucial Relation A path difference of exactly one wavelength ($\lambda$) corresponds to a phase difference of one full cycle ($2\pi$ radians). Therefore, the general relation is: $$\Delta\phi = \frac{2\pi}{\lambda} \Delta x$$ Memorize this formula. It is the key to solving interference problems.

4. Equation of a Progressive Wave

A progressive wave travels continuously in a medium in the same direction. We use a sinusoidal function to represent it.

General Equation For a wave traveling in the positive x-direction: $$y(x,t) = A \sin(\omega t - kx)$$ If it travels in the negative x-direction, the sign changes: $$y(x,t) = A \sin(\omega t + kx)$$

Let's break down the new symbols:

Notice that wave velocity can also be written as: $v = \frac{\omega}{k}$.

Practice Problem 2 Question: The equation of a transverse wave is given by $y = 5 \sin(100\pi t - 0.4\pi x)$, where $x$ and $y$ are in meters and $t$ is in seconds. Find the amplitude, frequency, wavelength, and wave velocity.
Sine Wave Graph Structure
Solution:
Compare the given equation with standard form: $y = A \sin(\omega t - kx)$

1. Amplitude ($A$): Direct comparison gives $\mathbf{A = 5 \text{ m}}$.
2. Angular Frequency ($\omega$): $\omega = 100\pi$.
Since $\omega = 2\pi f \implies 2\pi f = 100\pi \implies \mathbf{f = 50 \text{ Hz}}$.
3. Wave Number ($k$): $k = 0.4\pi$.
Since $k = \frac{2\pi}{\lambda} \implies \frac{2\pi}{\lambda} = 0.4\pi \implies \lambda = \frac{2}{0.4} = \mathbf{5 \text{ m}}$.
4. Velocity ($v$): $v = f \lambda = 50 \times 5 = \mathbf{250 \text{ m/s}}$.
*(Alternatively, $v = \frac{\omega}{k} = \frac{100\pi}{0.4\pi} = 250 \text{ m/s}$)*

5. Superposition and Interference

When two or more waves arrive at the same point simultaneously, what happens? They don't bounce off each other; they pass right through, adding their displacements together.

Principle of Superposition

"The resultant displacement of a particle at any instant is the vector sum of the displacements caused by the individual waves at that instant."

$$\vec{y}_{net} = \vec{y}_1 + \vec{y}_2 + \dots$$

Interference

Constructive and Destructive Interference

Constructive Interference (Maximum Intensity):
Occurs when crest falls on crest and trough on trough. The waves are "In Phase".
Phase Difference: $\Delta\phi = 0, 2\pi, 4\pi, \dots = 2n\pi$
Path Difference: $\Delta x = 0, \lambda, 2\lambda, \dots = \mathbf{n\lambda}$

Destructive Interference (Minimum Intensity):
Occurs when crest falls on trough. The waves are "Out of Phase" and cancel each other out.
Phase Difference: $\Delta\phi = \pi, 3\pi, 5\pi, \dots = (2n-1)\pi$
Path Difference: $\Delta x = \frac{\lambda}{2}, \frac{3\lambda}{2}, \dots = \mathbf{(n - \frac{1}{2})\lambda}$

Practice Problem 3 Question: Two sound waves of wavelength $2 \text{ m}$ reach a listener. The first wave travels $10 \text{ m}$ to reach the listener, while the second travels $13 \text{ m}$. Will the listener hear a loud sound (constructive) or no sound (destructive)?
Solution:
1. Find the path difference ($\Delta x$):
$\Delta x = x_2 - x_1 = 13 \text{ m} - 10 \text{ m} = 3 \text{ m}$.
2. Relate $\Delta x$ to wavelength ($\lambda = 2 \text{ m}$):
$\Delta x = 3 = 1.5 \times 2 = 1.5 \lambda$
Notice that $1.5 \lambda = \frac{3\lambda}{2}$.
3. Conclusion:
Since the path difference is an odd half-multiple of the wavelength, the waves arrive perfectly out of phase. This results in Destructive Interference. The listener will hear almost no sound.