CBSE Class 9 Science • Chapter 3 • Detailed Master Notes
Chapter Overview:
This chapter lays the foundation of Chemistry. It introduces the Laws of Chemical Combination, Dalton's Atomic Theory, the concept of Atoms, Atomic Mass, Molecules, writing Chemical Formulas, and the very important Mole Concept.
(i) Law of Conservation of Mass (Lavoisier):
Mass can neither be created nor destroyed in a chemical reaction. Total mass of reactants = Total mass of products.
(ii) Law of Constant Proportions (Proust):
In a pure chemical substance, elements are always present in definite proportions by mass.
e.g., In water ($H_2O$), ratio of mass of Hydrogen to Oxygen is always $1:8$, whatever the source.
The smallest particle of an element that retains its chemical properties.
Molecule: A group of two or more atoms chemically bonded. It can exist independently.
Ion: A charged species.
Formulae are written by crossing valencies.
Example: Magnesium Chloride
Example: Aluminium Oxide
This is the most critical calculation part of chemistry.
Sum of atomic masses of all atoms in a molecule.
e.g., $H_2O = 2 \times 1 + 16 = 18 u$.
A mole is a number unit (like a dozen = 12). It links mass and number of particles.
1 Mole = $6.022 \times 10^{23}$ particles (Avogadro No., $N_0$).
1 Mole atoms = Gram Atomic Mass of element.
e.g., 1 Mole Carbon atoms = $12g$ Carbon = $6.022 \times 10^{23}$ atoms.
Number of Moles ($n$):
Q1: Write formula of Calcium Carbonate.
Ans: Ca (+2), $CO_3$ (-2). Cross valencies: $CaCO_3$.
Q2: Convert 22g of Carbon Dioxide ($CO_2$) into moles.
Ans: Molar mass of $CO_2 = 12 + 2\times16 = 44g$.
Moles $n = m/M = 22/44 = 0.5$ moles.