CBSE Class 9 Science • Chapter 4 • Detailed Master Notes
Chapter Overview:
We know atoms are indivisible (Dalton). But discovery of electrons and protons challenged this. Here we study Sub-atomic particles, various Atomic Models (Thomson, Rutherford, Bohr), distribution of electrons in shells (Valency), and concepts of Isotopes and Isobars.
| Particle | Charge | Mass | Discoverer | Location |
|---|---|---|---|---|
| Electron ($e^-$) | -1 (Negative) | Negligible ($1/2000$ of H atom) | J.J. Thomson | Outside nucleus (Shells) |
| Proton ($p^+$) | +1 (Positive) | 1 unit | E. Goldstein | Inside nucleus |
| Neutron ($n$) | 0 (Neutral) | 1 unit | J. Chadwick | Inside nucleus |
He proposed that an atom is similar to a Christmas pudding or a Watermelon.
Fast moving alpha ($\alpha$) particles were made to fall on a thin Gold foil.
Observations:
Conclusions:
Drawback: Accelerating charged particle radiates energy. So electron should fall into nucleus, making atom unstable.
To overcome Rutherford's drawback, Neils Bohr proposed:
Rules for filling electrons:
Combining capacity of an atom.
Atomic Number (Z): Total number of protons in the nucleus. ($Z = p$). (Also equal to $e$ in neutral atom).
Mass Number (A): Sum of total number of protons and neutrons.
Notation: $_Z^A X$ (e.g., $_7^{14}N$ means Nitrogen with Z=7, A=14).
Isotopes: Atoms of the same element with same Atomic Number but different Mass Numbers.
Isobars: Atoms of different elements with different Atomic Numbers but same Mass Numbers.
e.g., Calcium ($^{40}_{20}Ca$) and Argon ($^{40}_{18}Ar$). Both have mass 40.
Q1: An atom has mass number 23 and atomic number 11. Find neutrons.
Ans: $n = A - Z = 23 - 11 = 12$ neutrons.
Q2: Write electronic configuration of Chlorine (Z=17).
Ans: K=2, L=8, M=7. ($2, 8, 7$). Valency = $8-7=1$.