CBSE Class 9 Science • Chapter 11 • Detailed Master Notes
Chapter Overview:
Sound is a form of energy that produces a sensation of hearing. In this chapter, we will explore:
Sound is produced due to the vibration of objects. Vibration means the rapid to-and-fro motion of an object.
Examples of Sound Production:
Note: The energy required to make an object vibrate is provided by some outside source (like our hand hitting a drum).
Sound waves are Mechanical Waves because they require a material medium (Solid, Liquid, or Gas) for their propagation. Sound cannot travel through a vacuum.
Mechanism of Propagation:
When an object vibrates, it sets the particles of the medium around it in vibration. These particles do not travel all the way from the source to the ear. instead:
Sound as Longitudinal Waves:
In sound waves, the individual particles of the medium move in a direction parallel to the direction of effective disturbance. Hence, sound waves are longitudinal.
Comparison: Light waves are Transverse waves (particles oscillate perpendicular to direction of propagation).
This experiment proves sound needs a medium.
A sound wave can be described by its Frequency, Amplitude, and Speed.
1. Wavelength ($\lambda$):
The distance between two consecutive compressions (C) or two consecutive rarefactions (R).
SI Unit: Meter ($m$).
2. Frequency ($\nu$ - nu):
The number of complete oscillations (waves) passing through a point in one unit of time.
SI Unit: Hertz ($Hz$).
3. Time Period ($T$):
The time taken by two consecutive compressions or rarefactions to cross a fixed point.
Relation: $T = \frac{1}{\nu}$. SI Unit: Second ($s$).
4. Amplitude ($A$):
The maximum magnitude of displacement of particles from their mean position. It determines the Loudness of the sound.
Pitch vs Loudness:
Relationship between Speed, Frequency, and Wavelength:
Speed = Distance / Time
Since usually distance $\lambda$ is covered in time $T$:
Speed ($v$) = Wavelength ($\lambda$) $\times$ Frequency ($\nu$)
Speed depends on the properties of the medium (Temperature, Density, Elasticity).
Sound bounces off a solid or liquid surface following the Laws of Reflection:
It is the repetition of sound caused by reflection of sound waves.
Condition for hearing distinct Echo:
Therefore, the minimum distance between the source and the reflector must be 17.2 meters.
The persistence of sound due to repeated reflection (even after the source stops) is called reverberation. It is often undesirable in concert halls.
How to reduce Reverberation:
| Types of Sound | Frequency Range | Details |
|---|---|---|
| Infrasonic | < 20 Hz | Produced by earthquakes, volcanoes, elephants, whales. (Felt as vibrations). |
| Audible Sound | 20 Hz - 20,000 Hz (20 kHz) | Humans can hear this range only. Sensitivity decreases with age. |
| Ultrasonic | > 20,000 Hz | Produced by bats, dolphins, porpoises. Used in medical scans (Ultrasound). |
A technique used to determine depth of sea or locate underwater hills/submarines using ultrasonic waves.
Working:
Where $d$ = depth, $v$ = speed of sound in water, $t$ = time taken.
The ear allows us to convert pressure variations in air with audible frequencies into electric signals.
Q1: A person claps his hands near a cliff and hears the echo after 4 seconds. What is the distance of the cliff from the person if the speed of sound, $v = 346 m/s$?
Ans: Time taken for echo return $t = 4 s$. Speed $v = 346 m/s$.
Distance travelled $= 2d = v \times t$.
$2d = 346 \times 4 = 1384 m$.
$d = 1384 / 2 = 692 m$.
Q2: A ship sends out ultrasound that returns from the seabed and is detected after 3.42 s. If the speed of ultrasound through seawater is 1531 m/s, what is the distance of the seabed from the ship?
Ans: $t = 3.42 s$, $v = 1531 m/s$.
$d = \frac{v \times t}{2} = \frac{1531 \times 3.42}{2} = \frac{5236.02}{2} = 2618.01 m$.
Q3: Why are the ceilings of concert halls curved?
Ans: Ceilings are curved so that sound after reflection reaches all corners of the hall evenly. This prevents dead spots and ensures clearer audibility.