ICSE Class 10 Mathematics • Chapter 11
Central Angle: Angle at the center of the circle.
Inscribed Angle: Angle at any point on the circle (vertex on circumference).
Central Angle = 2 × Inscribed Angle
(if both subtend the same arc)
Theorem: Angles in the same segment of a circle are equal.
All inscribed angles subtending the same arc are equal.
Theorem: An angle inscribed in a semicircle is a right angle (90°).
If AB is a diameter and C is any point on the circle, then ∠ACB = 90°
Cyclic Quadrilateral: A quadrilateral whose all four vertices lie on a circle.
Property 1: Opposite angles of a cyclic quadrilateral are supplementary.
∠A + ∠C = 180° and ∠B + ∠D = 180°
Property 2: Exterior angle of cyclic quadrilateral = Interior opposite angle.
Tangent: A line that touches the circle at exactly one point (point of tangency).
Theorem 1: The tangent at any point of a circle is perpendicular to the radius at that point.
If PT is tangent at T, then OT ⊥ PT (∠OTP = 90°)
Theorem 2: Tangents drawn from an external point to a circle are equal in length.
If PA and PB are tangents from P, then PA = PB
Additional Properties (Two Tangents from External Point):
Theorem: If two chords intersect inside a circle, then:
PA × PB = PC × PD
(Product of segments of one chord = Product of segments of other chord)
Theorem: If a tangent and a secant are drawn from an external point:
(Tangent)² = External segment × Whole secant
PT² = PA × PB
Theorem: The angle between a tangent and a chord at the point of contact equals the inscribed angle in the alternate segment.
∠PTB = ∠BAT (angle in alternate segment)
Example 1: In a circle, inscribed angle is 35°. Find the central angle subtending the same arc.
Central angle = 2 × Inscribed angle = 2 × 35° = 70°
Example 2: In cyclic quadrilateral ABCD, ∠A = 70° and ∠B = 115°. Find ∠C and ∠D.
∠C = 180° − ∠A = 180° − 70° = 110°
∠D = 180° − ∠B = 180° − 115° = 65°
Example 3: Two chords AB and CD intersect at P. If AP = 4, PB = 6, CP = 3, find PD.
AP × PB = CP × PD
4 × 6 = 3 × PD
PD = 8 cm
| Theorem | Statement |
|---|---|
| Central = 2 × Inscribed | ∠at center = 2 × ∠at circumference |
| Same Segment | Angles in same segment are equal |
| Semicircle | Angle in semicircle = 90° |
| Cyclic Quadrilateral | Opposite angles add to 180° |
| Tangent ⊥ Radius | Tangent perpendicular to radius |
| Equal Tangents | Tangents from external point are equal |
| Intersecting Chords | PA × PB = PC × PD |
| Tangent-Secant | PT² = PA × PB |
BOARD In the figure, O is center of circle. ∠AOB = 100°. Find ∠ACB and ∠ADB if C and D are points on the major and minor arcs respectively.
BOARD PA and PB are tangents to a circle with center O. If ∠APB = 80°, find: (i) ∠AOB (ii) ∠OAB