Algebra is the language of Physics. Every single physical equation — from Newton's second law ($F = ma$) to Einstein's mass–energy equivalence ($E = mc^2$) — is an algebraic relationship. Mastering manipulation of these equations is the very first skill a Physics student must develop.
When quantities are raised to powers, we use the following rules to simplify them:
$a^m \cdot a^n = a^{m+n}$
Ex: $a^3 \cdot a^5 = a^8$
$\frac{a^m}{a^n} = a^{m-n}$
Ex: $\frac{x^7}{x^3} = x^4$
$(a^m)^n = a^{mn}$
Ex: $(x^2)^3 = x^6$
$a^0 = 1 \quad a^{-n} = \frac{1}{a^n}$
Ex: $x^{-2} = \frac{1}{x^2}$
$a^{1/n} = \sqrt[n]{a}$
Ex: $x^{1/2} = \sqrt{x}, \quad x^{3/2} = x\sqrt{x}$
$(ab)^n = a^n b^n$
$(\frac{a}{b})^n = \frac{a^n}{b^n}$
Gravitational force $F \propto r^{-2}$, Electric field $E \propto r^{-2}$ — these negative exponents come directly from index laws!
A quadratic equation has the standard form: $ax^2 + bx + c = 0$, where $a \neq 0$.
The term $\Delta = b^2 - 4ac$ is called the Discriminant. It tells us the nature of roots:
If $\alpha$ and $\beta$ are the two roots of $ax^2 + bx + c = 0$, then:
Solved Example: Find the roots of $2x^2 - 7x + 3 = 0$.
Here, $a = 2, b = -7, c = 3$.
$\Delta = b^2 - 4ac = 49 - 24 = 25$
$x = \frac{7 \pm \sqrt{25}}{4} = \frac{7 \pm 5}{4}$
$\therefore x = \frac{12}{4} = 3 \quad \text{or} \quad x = \frac{2}{4} = \frac{1}{2}$
When solving projectile motion problems for time of flight (the ball returns to ground), you get a quadratic equation in time $t$: $h = ut - \frac{1}{2}gt^2$, giving $t$ via the quadratic formula.
Graph: Comparing exact $(1 + x)^2$ vs. approximation $1 + 2x$ for small values of x
The Binomial Theorem gives the expansion of $(1 + x)^n$ for any real value of $n$:
All higher-power terms of $x$ become negligibly small and can be dropped.
Solved Example: Simplify $\sqrt{1 + 0.02}$ approximately.
Write as $(1 + 0.02)^{1/2}$. Here $n = 1/2$ and $x = 0.02$ (which is $\ll 1$).
$\approx 1 + \frac{1}{2}(0.02) = 1 + 0.01 = \mathbf{1.01}$
(Exact value: 1.00995 — the approximation is extremely accurate!)
A sequence where each term differs by a constant amount (common difference, $d$).
General form: $a, \ a + d, \ a + 2d, \ a + 3d, \dots$
A sequence where each term is obtained by multiplying the previous by a constant (common ratio, $r$).
General form: $a, \ ar, \ ar^2, \ ar^3, \dots$
(only if $|r| < 1$)
Solved Example (Infinite GP): Find $1 + \frac{1}{3} + \frac{1}{9} + \frac{1}{27} + \dots$
Here $a = 1$, $r = 1/3$ (which is $|r| < 1$).
$S_\infty = \frac{1}{1 - 1/3} = \frac{1}{2/3} = \frac{3}{2} = \mathbf{1.5}$
Multiple reflections in optics (finding total intensity of light bouncing between two parallel mirrors), Electrostatics problems with image charges — all use the infinite GP sum formula.
If $\frac{a}{b} = \frac{p}{q}$, then by Componendo & Dividendo:
This rule allows you to manipulate ratio equations without full cross-multiplication.
Solved Example: If $\frac{x + 1}{x - 1} = \frac{3}{2}$, find $x$.
Using Componendo & Dividendo (comparing $\frac{a}{b} = \frac{3}{2}$ where $a = x + 1, b = x - 1$):
$\frac{(x + 1) + (x - 1)}{(x + 1) - (x - 1)} = \frac{3 + 2}{3 - 2} \implies \frac{2x}{2} = \frac{5}{1}
\implies \mathbf{x = 5}$
| Q | Answer & Method |
|---|---|
| 1 | $x^0 = \mathbf{1}$. Powers: $5 + (-2) - 3 = 0$. |
| 2 | $(27)^{2/3} = (\sqrt[3]{27})^2 = 3^2 = \mathbf{9}$. |
| 3 | $\frac{a^4 b^6}{a^3 b^4} = \mathbf{ab^2}$. |
| 4 | $2^x = 2^4 \implies \mathbf{x = 4}$. |
| 5 | $\left(\frac{y^3}{x^3}\right)^3 = \mathbf{\frac{y^9}{x^9}}$. |
| 6 | Factor: $(x - 2)(x - 3) = 0 \implies \mathbf{x = 2, 3}$. |
| 7 | $\mathbf{x = 3/2} \text{ or } \mathbf{x = -2}$. [Use quadratic formula or factor as $(2x - 3)(x + 2) = 0$] |
| 8 | $\Delta = 16 - 24 = \mathbf{-8} < 0$. No real roots. |
| 9 | $p = -(3 + 4) = \mathbf{-7}, \quad q = 3 \times 4 = \mathbf{12}$. |
| 10 | $(x + 2)(x - 5) = 0 \implies \mathbf{x^2 - 3x - 10 = 0}$. |
| 11 | $\approx 1 + 10(0.01) = \mathbf{1.10}$. (Exact: 1.10462) |
| 12 | $(1 - 0.04)^{-1/2} \approx 1 + \frac{1}{2}(0.04) = \mathbf{1.02}$. |
| 13 | $\frac{R^2}{(R+h)^2} = \left(1 + \frac{h}{R}\right)^{-2} \approx 1 - \frac{2h}{R}$. So $g' \approx g\left(1 - \frac{2h}{R}\right)$. $\checkmark$ |
| 14 | $(1 - 0.01)^8 \approx 1 + 8(-0.01) = \mathbf{0.92}$. |
| 15 | Show that for small $x$: $(1 - x)^{-1} \approx 1 + x$ $\checkmark$ |
| 16 | $a_{15} = 3 + 14(4) = \mathbf{59}$. |
| 17 | $155 = \frac{10}{2}(4 + 9d) \implies d = \mathbf{3}$. |
| 18 | $a_6 = 2 \cdot 3^5 = 2 \times 243 = \mathbf{486}$. |
| 19 | $a = 8, \ r = 1/2. \ S_\infty = \frac{8}{1-0.5} = \mathbf{16}$. |
| 20 | Means: 10, 15, 20. [AP: 5, 10, 15, 20, 25 with $d=5$] |
| 21 | $5t^2 - 20t = 0 \Rightarrow t(5t-20)=0 \Rightarrow t = \mathbf{0s, 4s}$. |
| 22 | Error in volume $\approx 3 \times 2\% = \mathbf{6\%}$ (binomial: $(1+0.02)^3 \approx 1+0.06$). |
| 23 | $a=1/2, r=1/2$. $S_\infty = \frac{0.5}{0.5} = \mathbf{1}$. |
| 24 | Comp & Divid: $\frac{2v}{2u}=\frac{4}{2} \Rightarrow v = \mathbf{2u}$. |
| 25 | $n(n+1)=182 \Rightarrow n^2+n-182=0 \Rightarrow n=\mathbf{13}$ (integers: 13, 14). |
| 26 | Infinite GP with $a=q_0, r=r$. $S_\infty = \mathbf{\frac{q_0}{1-r}}$. |
| 27 | $(2x-1)(x-1)=(x-2)(x+3) \Rightarrow \mathbf{x = 7 \text{ or } -1}$. |
| 28 | $S_n = \frac{n}{2}[2(1)+(n-1)(1)] = \mathbf{\frac{n(n+1)}{2}}$. |
| 29 | $\Delta = 0 \Rightarrow k^2 - 4(3)(12)=0 \Rightarrow k = \pm\mathbf{12}$. |
| 30 | $\frac{64 \cdot \frac{1}{4}}{4} = \frac{16}{4} = \mathbf{4}$. |